If in a triangle ABC, angleA+ angleB =105, angleB+angleC= 120 then angleB is:
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∠A+∠B+∠C=180° ----1 (Sum of angles in a triangle is 180°)
Given
∠A+∠B=105° ----2
∠B+∠C=120° ----3
From 1 and 3,
∠A=60° ----4
From 4 and 2,
∠B=45° ---5
VERIFICATION
From 3 and 5,
∠C=75°
∠A+∠B+∠C=60°+45°+75°=180°
Given
∠A+∠B=105° ----2
∠B+∠C=120° ----3
From 1 and 3,
∠A=60° ----4
From 4 and 2,
∠B=45° ---5
VERIFICATION
From 3 and 5,
∠C=75°
∠A+∠B+∠C=60°+45°+75°=180°
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