If in a triangle ABC anglebA + angle B = 105° angle B + angle C = 120° then find the value of angle B
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Answered by
1
Answer:
B = 55 but the question is wrong
Step-by-step explanation:
a+b = 105
b+c = 120
sum of all interior angles a of a triangle is 180
120 is b+c so here A is missing so
180 - 120 = A
A=50
and in A+B is 105 so
105 - 50 =55
which is angle B
B = 55
Answered by
1
Answer:
In triangle ABC
angleA + angleB + angleC = 180°
105°+ angle C = 180°
angle C =180° - 105°
angle C = 75°
angle B + angle C = 120°
angle B + 75° = 120°
angle B = 120° - 75°
angle B = 45°
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