Question

If in a triangle abc, be and cf are two medians perpendicular to each other and if ab = 19cm and ac = 22 cm then the length of bc is​

Answer 1

Answer:

bc^2 = ab^2 + ac^2

bc^2 = 19cm^2 + 22cm^2

bc^2 = 301cm + 484cm

bc. = √785

bc. = 265cm