If in a triangle abc , LA+LB=105 , LB+LC=120 Find LB
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∠A+∠B=105
∠B+∠C=120
in ΔABC,
∠A+∠B+∠C=180
⇒105+∠C=180
⇒∠C=180-105
⇒∠C=75
∠B+∠C=120
⇒∠B+75=120
⇒∠B=120-75
⇒∠B=45
∠B+∠C=120
in ΔABC,
∠A+∠B+∠C=180
⇒105+∠C=180
⇒∠C=180-105
⇒∠C=75
∠B+∠C=120
⇒∠B+75=120
⇒∠B=120-75
⇒∠B=45
lekhahasa:
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