Math, asked by coolmangmailcom954, 1 year ago

If in a triangle ABC right angled at B, AB=6 units and BC=8 units,then find the value of sinA. cosC + cos A. sinC

Answers

Answered by marco417chan

4

the length of AC: root(8^2+6^2)=10

A+C=180-B=90 (angle sum of triangle)

sinA*cosC+sinC*cosA=sin(A+C)=sin90=1

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