Question

If in a triangle LMN:
(a) ZL = 80°, ZM = 50°, find ZN.​

Answer 1

Answer:

ZL+ZM+ZN=180 degrees

80+50+ZN=180

ZN=180-130

ZN=50 degree Answer

Answer 2

Answer:

In △LMN

∠L+∠M+∠N=180

∘

60

∘

+50

∘

+∠N=180

∘

⇒∠N=70

∘

Now ,

△LMN∼△PQR

∴∠R=∠N

⇒∠N=70 degree

Step-by-step explanation:

hope it helps