Question

If in a vernier calliper n VSD coincides with (n - 1)
MSD, then the least count of vernier calliper is (Take 1
MSD = 1 mm)

a. (n-1) mm
b. n mm
c. {1/n-1} x mm
d. {1/n}mm​

Answer 1

Answer :

In a vernier calliper n VSD coincides with (n-1) MSD.

We have to find least count of vernier calliper$.$

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As given, n VSD = (n-1) MSD

VSD = Vernier scale divison

MSD = Main scale divison

፨ 1 VSD = (n-1)/n MSD

We know that,

• Least count = 1MSD - 1VSD

⇒ LC = 1 - [(n-1)/n] MSD

⇒ LC = [n-n-1]/n MSD

⇒ LC = 1/n MSD

[፨ 1MSD = 1mm]

⇒ LC = 1/n mm