Question

If in a vernier callipers 10 VSD coincides with 8 MSD then the least count of the Vernier callipers is

Answer 1

∵ 10th V.S.D concides with 8th M.S.D
so, 1 V.S.D = 8/10 M.S.D = 0.8 M.S.D

Also we know, 1 M.S.D = 1 mm
Now, least count = 1 M.S.D - 1 V.S.D
= 1 M.S.D - 0.8 M.S.D
= 0.2 M.S.D
= 0.2 × 1 mm [∵ 1M.S.D = 1mm ]
= 0.2 mm

Hence, least count = 0.2 mm

Answer 2

Answer: THE ANSWER FOR THIS IS :

0.2mm

Explanation:

Given,

1 msd = 1 mm

10th  vsd coincides with the 8th  msd.

therefore, 1 vsd = 8/10 msd = 8/10 × 1 mm = 0.8 mm

thus, least count = 1 msd – 1 vsd = 1 mm – 0.8 mm = 0.2 mm

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