Question

If in a Young's double slit experiment, the slit width is 3cm, the separation between slits and screen is 70cm and wavelength of light is 1000angstrom, then fringe width is

Answer 1

Answer:

n Young's double slit experiment, slit separation is 0.6mm and the separation between slit and screen is 1.2m. The angular width is (the wavelength of light used is 4800Å)

Explanation:

Answer 2

Answer:

fringe width = $\frac{\lambda D}{d}$

given:

λ = 1000 A = 1 * 10⁻⁷ m

D = 0.7 m

d = 0.03 m

so ,

fringe width = 1*10⁻⁷ * 0.7 / 0.03

                    = 2.333 * 10⁻⁷ m