If in AABC, ZB =90", AB = 12 cm and BC- 5cm then the value of cosc is
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Answer:
△ABCis a right angled triangle
AC
2
=BC
2
+AB
2
AC
2
=(5)
2
+(12)
2
AC
2
=25+144
AC
2
=169=(13)
2
or AC=13
Now from figure,
i.cosA=
AC
AB
=
13
12
ii.cscA=
BC
AC
=
5
13
iii.cosC=
AC
BC
=
13
5
iv.cscC=
AB
AC
=
12
13
Hence, proved.
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Class 10
>>Maths
>>Introduction to Trigonometry
>>Trigonometric Identities
>>In a ABC angle B = 90 degree, AB = 12
Question

In a △ABC angle B = 90 degree, AB = 12 cm and BC = 5 cm
Find (i) cos A (ii) cosec A (iii) cos C (iv) cosec C
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Solution

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From figure: △ABCis a right angled triangle
AC2=BC2+AB2
AC2=(5)2+(12)2
AC2=25+144
AC2=169=(13)2
or AC=13
Now from figure,
i.cosA=ACAB=1312
ii.cscA=BCAC=513
iii.cosC=ACBC=135
iv.cscC=ABAC=1213
Hence, proved.
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