Question

If in ∆ABC, A = 70°, B = 50°, C = 60°, then the ascending order of the sides is (plz explain)
(A) AB <BC < AC (B) BC < AB < AC
(C) AC < AB <BC (D) None​

Answer 1

Answer:

Using angle sum property in △ABC

∠A+∠B+∠C=180

∘

⇒50

∘

+60

∘

+∠C=180

∘

⇒∠C=70

∘

In any triangle side opposite to the largest angle is the longest side.

Here ∠C is largest and side opposite to it is AB

∴AB is the longest side.

Then comes ∠B and side opposite to it is AC

∴AC is the second longest side.

Then comes ∠A and side opposite to it is AC

∴BC is the shortest side.

So the increasing order of sides is

BC<AC<AB