If in ΔABC, ∠A + ∠B = 110 °and ∠B + ∠C = 150° , find ∠B.
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Answer:
(<A+<B)+zC=180° (angle sum property)
150°+2C=180°
ZC-180°-150°
ZA+(2B+ZC)=180° (angle sum property)
ZA+100=180°
ZA=180°-100°
..ZA=80°
ZA+ZB+ZC=180° (angle sum property)
80°+B+30°=180°
ZB=180°-110°
..<B=70°
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