if in ∆ABC,AB=15cm, BC=17cm and AC =8cm ,then which of the following will be a right angle
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In a right angle traingle, Pythagoras theorem will hold good.
(Hypotenuse)^2=(Perpendicuar)^2+(Base)^2
=> (BC)^2 = (AB)^2+(AC)2
=> (17)^2=(15)^2+(8)^2
=>289=225+64
=> 289=289
=> L.H.S.=R.H.S.
So, the triangle under question is certainly a right angle triangle and it is right angle at A.
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