Question

If in ∆ABC , angle ABC=90° and BD is perpendicular to AC. If AD=8cm and CD=2cm, find BD

Answer 1

By the theorem of geometric mean

${bd}^{2} = ad \times cd$

${bd}^{2} = 8 \times 2$

${bd}^{2} = 16$

$bd = \sqrt{16}$

bd = 4 cm

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