. If in ΔABC, ∠C = 90°, then sin (A + B) =
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Given :-
- in triangle abc, angle c=90°
To Find :-
- sin(a+b)
Solution:-
In any triangle sum of all angles of triangle is 180°
Hence ∠a + ∠b + ∠c = 180°
∠c = 90° given
⇒∠a + ∠b + 90° = 180°
⇒∠a + ∠b = 90°
⇒ sin(a+b) = Sin 90°
⇒ sin(a+b) = 1
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