If in ∆ABC tanA=3/4 and angleC=90° then find.
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Answers
Answered by
1
Step-by-step explanation:
Given ∠B=90
0
∴B−C=A
Thus using above formula, tan(
2
B−C
)=
b+c
b−c
cot
2
A
⇒tan
2
2
A
=
b+c
b−c
Answered by
2
Answer:
43/18
Step-by-step explanation:
given,tanA=3/4
then perpendicular=3 and base=4 so from pythagoras theorem, we get hypotenuse=5.
therefore,secA=hypotenuse/base and tanA=penpendicular/base
then, sec2A+2tan2A
=(5/4)2 +2*(3/4)2
=25/16 +2*9/16
=25/16+9/8
=25+18/16
=43/16
=2.68
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