Question

if in an A.P a3=12 and a6=33 then find s10​

Answer 1

Answer:

given,

a3 =12

then, a+2d = 12 ------(eq1)

and a +5d = 33 -----(eq2)

solve 1 and 2

then you will get d value

and substitute it in either eqns 1 and 2

you will get the value of a and d

now S10 = 10/2 ×2a + (n -1) d

solve it then you will get the answer

Step-by-step explanation:

PLSE... MARK ME AS BRAINLIEST

Answer 2

Answer:

a3= a+2d=12

a6= a+5d=33

solving both the equations

3d=21

d=7

therefore a=(-2)

a10= (-2)+63

a10= 61

s10= 10/2[(-2)+61]

s10 = 5*59

295= s10...