if in an a.p.
an=m
am=n
a(n+m)=?
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Answers
Answered by
1
Answer:
0
Step-by-step explanation:
am = a + (m – 1)d
an = a + (n - 1)d
It is given that
m(am) = n(an)
m{a + (m – 1)d} =n{a+ (n – 1)d}
ma + m(m – 1)d = na + n(n – 1)d
ma — na = = d(n² – n – m² +m)
a(m – n) = d(n – m)(m +n – 1)
a = -d(m +n - 1)
a+(m+n-1)d=0
Now (m + n)th term is
a(m+n) = a+(m+n – 1)d
= 0
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