If in an A. P., d = 10, find t6
- t2
.
saurabhsemalti:
yup
Answers
Answered by
12
if d=10
then
tn=a+(n-1)d
t6=a+5d......(1)
t2=a+d..........(2)
sub (1)-(2)
t6-t2=(a+5d)-(a+d)=4d=4*10=40
then
tn=a+(n-1)d
t6=a+5d......(1)
t2=a+d..........(2)
sub (1)-(2)
t6-t2=(a+5d)-(a+d)=4d=4*10=40
Answered by
3
Answer:
Step-by-step explanation:
D=6
t6 =a+(n-1)d
T6=a+5d =a+30
T12= a+ (n-1)d
T12 = a + 11d =a+66
Subtract
T6-t12
A+20-a-66
-46
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