If in an A.P series 18th term is 29 and 29th term is 18. Then find the 49th term ?
A) -3
B) -2
C) 0
D) 1
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Let the first term be 'a'and the common difference be 'd'.
Given 18th term (a+17d) = 29 -------(1)
29th term (a+28d)= 18 -------(2)
Now, (2)-(1)» (a+28d)-(a+17d)=18-29
»a+28d-a-17d=-11
»11d=-11
»d=-11/11
Therefore, d=-1
Putting d=1 in (1) we get,
»a+17×(-1)=29
»a-17=29
»a=29+17
»a=46
Now, 49th term = a+48d
»49th term = 46+48×(-1)
»49th term = 46-48
Therefore, 49th term = -2
Hope this answer helps you mate.
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Given 18th term (a+17d) = 29 -------(1)
29th term (a+28d)= 18 -------(2)
Now, (2)-(1)» (a+28d)-(a+17d)=18-29
»a+28d-a-17d=-11
»11d=-11
»d=-11/11
Therefore, d=-1
Putting d=1 in (1) we get,
»a+17×(-1)=29
»a-17=29
»a=29+17
»a=46
Now, 49th term = a+48d
»49th term = 46+48×(-1)
»49th term = 46-48
Therefore, 49th term = -2
Hope this answer helps you mate.
Please mark me as the brainliest one.
Thank you.
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