Question

If in an AP, 8th term is 4 and 16th term is -20, then find the common difference of the given AP.​

Answer 1

Answer:

Solution :

\: \: \: \: \: \: \: \: \: \:3x - \frac{8}{x} = 23x−

x

8

=2

= > \frac{ {3x}^{2} - 8}{x} = 2=>

x

3x

2

−8

=2

= > {3x}^{2} - 8 = 2x=>3x

2

−8=2x

= > {3x}^{2} - 2x - 8 = 0=>3x

2

−2x−8=0

= > {3x}^{2} - 6x + 4x - 8 = 0=>3x

2

−6x+4x−8=0

= > 3x(x - 2) + 4(x - 2) = 0=>3x(x−2)+4(x−2)=0

= > (x - 2)(3x + 4)=>(x−2)(3x+4)

= > x - 2 = 0 \: \: \: \: or \: \: \: \: 3x + 4 = 0=>x−2=0or3x+4=0

= > x = 2 \: \: \: \: or \: \: \: \: 3x = - 4=>x=2or3x=−4

= > x = 2 \: \: \: \: or \: \: \: \: x = \frac{ - 4}{3}=>x=2orx=

3

−4