Question

If in an AP, a=6, d=-2, and an=0, then find the value of n

Answer 1

Hope this would be helpfull bro...

Answer 2

Answer:

n = 4

Given:-

• a =6
• d = -2
• an = 0

To find:-

• find the value of n

solution:-

as we know

formula of tn

$t_{n} = a + (n - 1) \times d \\ \\ put \: all \: the \: value \\ \\ 0 = 6 + (n - 1) \times - 2 \\ \\ 6 + ( - 2n + 2) = 0 \\ \\ 6 - 2n + 2 = 0 \\ \\ - 2n = - 8 \\ \\ n = \frac{ - 8}{ - 2} \\ \\ n = 4$