Question

If in an AP d= -2, n= 5 and an =0, what is the value of a

Answer 1

Answer:

d = -2, n = 5, an = 0

an = a+(n-1) d

0 = a+(5-1) × -2

0 = a+4 × -2

0 = a - 8

8+0 = a

8 = a

Answer 2

Answer:

$an = 0 \\ d = - 2 \\ n = 5 \\ \\ general \: term \: of \: ap \: \: \: \: \: an = a + (n - 1)d \\ \\ 0 = a + (5 - 1) \times - 2 \\ 0 = a + 4 \times - 2 \\ 0 = a - 8 \\ a = 8$

I hope u will find ur answer plz mark brainliest answer