if in an ap ratio of 4th term and 9 term is 1 :3 find the ratio of 12th and 5th term.
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this solution and ratio is 3:1
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4th term = a+3d
9th term = a +8d
it is given that ratio is 1:3
thus,
a + 3d 1
---------- = ----
a + 8 d 3
cross multiple we get,
3(a+3d) = a+8d
3a+9d=a+8d
2a+d=0
d= - 2a ------------------1
a12 : a5
12 th term= a+11d
5 th term a + 4d
a + 11d
ratio = ----------- ------------2
a + 4d
substitute 1 in 2 we get,
= a+( 11* -2a)
-------------------
a +(4* -2a)
= a-22a
----------
a - 8a
-21a
= ----------
-7a
= 3/1
thus,
the ration between 12th and 5th term is also 3:1
hope it helps!!!!
9th term = a +8d
it is given that ratio is 1:3
thus,
a + 3d 1
---------- = ----
a + 8 d 3
cross multiple we get,
3(a+3d) = a+8d
3a+9d=a+8d
2a+d=0
d= - 2a ------------------1
a12 : a5
12 th term= a+11d
5 th term a + 4d
a + 11d
ratio = ----------- ------------2
a + 4d
substitute 1 in 2 we get,
= a+( 11* -2a)
-------------------
a +(4* -2a)
= a-22a
----------
a - 8a
-21a
= ----------
-7a
= 3/1
thus,
the ration between 12th and 5th term is also 3:1
hope it helps!!!!
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