Question

If in certain language CALCUTTA is coded as GEPGYXXE
which word will be coded as FSQFCE?
a) BOMBYA b) BOMBAY c) BOMYAB
d) BOBAYM e) None of these
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Answer 1

Seems that each letter of CALCUTTA is advanced by four to be GEPGYXXE. Mea s...

Fourth letter after C is G.

Fourth letter after A is E.

Fourth letter after L is P.

Fourth letter after U is Y.

Fourth letter after T is X.

So, in the case of FSQFCE, each letter has to go 4 letters before to be the original word.

Fourth letter before F is B.

Fourth letter before S is O.

Fourth letter before Q is M.

Fourth letter before C is ???

Let's find.

Position number of C is 3. So the position number of fourth letter before C becomes 3 - 4 = -1. As there's no -1st letter, this -1 is added from the total no. of letters, i.e., 26, so that 26 - 1 = 25.

25th letter is Y.

Therefore, fourth letter before C is Y.

Fourth letter before E is A.

Therefore, FSQFCE = BOMBYA.

So the answer is not BOMBAY, it's option (a).