Question

If in coded language
SUHANI = 22
VANDANA = 54
NITIKA = 34
Then
MOONIKA = ?

Answer 1

Solutions :-


Alphabetical codes :

A = 1, B = 2, C = 3, D = 4, E = 5, F = 6, G = 7, H = 8, I = 9, J = 10, K = 11, L = 12, M = 13, N = 14, O = 15, P = 16, Q = 17, R = 18, S = 19, T = 20, U = 21, V = 22, W = 23, X = 24, Y = 25, Z = 26


We get the answer after adding the even numbers.

First case,
SUHANI
S = 19
U = 21
H = 8
A = 1
N = 14
I = 9

Even number in SUHANI = (8 + 14)
= 22


Second case,
VANDANA
V = 22
A = 1
N = 14
D = 4
A = 1
N = 14
A = 1

Even numbers in VANDANA = (22 + 14 + 4 + 14)
= 54


Third case,
NITIKA
N = 14
I = 9
T = 20
I = 9
K = 11
A = 1

Even numbers in NITIKA = (14 + 20)
= 34


Therefore,
MOONIKA
M = 13
O = 15
O = 15
N = 14
I = 9
K = 11
A = 1

Even numbers in MOONIKA = 14

Hence,
MOONIKA = 14

Answer 2

S- 19. U -21, H - 8 , A-1 , N-14, I - 9

Now its 22 that is even

Now we have 6 nos. in which 4 are odd and 2 are even

3 odds we can't take

2 even with 1 odd can't take

2 even with 3 odd we can't take

Only possibility is

All 4 odd + All even = 72

All even -8 +14 - 22

2 odd + 1 even -
( As there are 4 odd and 2 even

So 6× 2 = 12 ways are there
(19+ 21 +8) = 48
( 19 +1 +8) = 28
( 19+ 9 +8) = 36
( 21 +1 +8) = 30
( 21 + 9 +8) = 38
( 1 + 9 +8) = 18

These are 6 possibilities ,now take 14 instead of 8 to get another 6

As all are greater than 22 except 18 but after taking 14 it would become greater

2 odd + 2 even - ( As 2 odd + 1 even is larger so by taking both even it would become more larger)

4 odd + 1 even - 19 +21 +1 +9 +8 = 58
Another even is more larger so it would be greater than 58


4 odd + 2 even - As 2 odd +2even is larger so 4 odd + 2 even would be more larger

So its sum of All even -8+14 = 22


VANDANA -54

V- 22, A-1 ,N - 14, D- 4, A-1 ,N - 14, A- 1

TAKE ALL EVEN

22 +14 + 14 +4 = 54

NITIKA-34

N- 14. I - 9, T- 20, I -9 , K- 11, A-1

TAKE ALL EVEN

14+20 = 34


SO MOONIKA

M- 13, O- 15, O-15, N- 14, I - 9, K- 11, A-1

Take all even

As only 14 is even

So its 14 ..