Question

If in concave mirror object is placed at 16cm and and height of that object is 2cm and focal length is 20cm find position of image,nature and magnification​

Answer 1

Answer:

Position of image = between F and P (8.88cm)

Nature of image = diminished

Magnification: m<-1 (-0.55)

Explanation:

We have

f =20

u= -16(concave mirror)

Height of image = 2

Firstly by the formula

1/f = 1/v +1/u We put our values in it

1/20 = 1/v + 1/-16

~by solving we get

v = 80/9 or 8.88 this v denotes the distance of image from the mirror and since it’s a concave mirror the image will be formed on the same side, that too real and inverted.

Now for the magnification although we can say it directly that since it’s a concave mirror it’s magnification will always be m< -1 But for finding it we can put our values in the formula : m = v/u

m = 80/9*(-16)

~ by solving we get m= -5/9 or -0.55 ( m< -1)