Question

If in Fig 6.1, O is the point of intersection of two chords AB and CD such that OB = OD, then triangles OAC and ODB are

(A) equilateral but not similar
(B) isosceles but not similar
(C) equilateral and similar
(D) isosceles and similar

Justify your answer​

Answer 1

Answer:

c) answer is the equilateral and similar Mark me brainliest

Answer 2

OC=OA =OD=OB (radius of circle)

AOC=BOD=45° (VOA)

OAC=OCA be =x (angles opposite to equal side of equilateral ∆ are equal)

x+x+45°=180° (Total sum of all angles of ∆ is 180°)

2x+45°=180

2x =180°-45°

2x=135°

x=67.5°

AOC = COA = BOD = DOB =67.5° (VOA)

Therefore the two triangles are similar.