If in Fig 6.1, O is the point of intersection of two chords AB and CD such that OB = OD, then prove taht triangles OAC and ODB are isoceles
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7
Heyy mate ❤✌✌❤
Here's your Answer...
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In triangle OAC,
OA = OC ( RADIUS OF THE CIRCLE)
THEREFORE, OAC IS A ISOSCELES TRIANGLE.
IN TRIANGLE OBD,
OB = OD ( RADIUS OF THE CIRCLE)
THEREFORE , OBD IS A ISOSCELES TRIANGLE.
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Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️
In triangle OAC,
OA = OC ( RADIUS OF THE CIRCLE)
THEREFORE, OAC IS A ISOSCELES TRIANGLE.
IN TRIANGLE OBD,
OB = OD ( RADIUS OF THE CIRCLE)
THEREFORE , OBD IS A ISOSCELES TRIANGLE.
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11
wish you happy new year mate
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