Question

If in Hydrogen atom, an electron jumps from ng= 2 to n = 1 in Bohr's orbit, then the value of wave
number of the emitted photon will be (R = 109700 cm-)
[ ]
1) 54850 cm-
2) 82275 cm-1
3) 62875 cm-1
4) 10970 cm
​

Answer 1

Answer:

answer is 1)

Explanation:

wave no. = 109700[1/1-1/2]

= 109700×(1-0.5)

=109700×(0.5)

=54850

hope it helps u!!

Answer 2

Hope it helps you plzz mark me brainliest