If. In the figure, line PQ and RS intersect at O. angel QOR = 44º. Find angelx, angle y and anglez.
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POR+∠ROQ=180
o
(Linear pair of angles)
But ∠POR:∠ROQ=5:7 (Given)
Therefore, ∠POR=
12
5
×180=75
o
Similarly, ∠ROQ=
12
7
×180=105
o
Now, ∠POS=∠ROQ=105
o
(Vertically opposite angles)
and ∠SOQ=∠POR=75
o
(Vertically opposite angles)
Answered by
0
Answer:
angle X = 44
_ here angle QOR and angle Y form a linear pair
hence 44+Y =180
Y =180-44
Y =136
- here Y and Z are vertically opposite
so Y=Z
hence Z = 136
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