Question

if in the given reaction 3I2 + oh gives IO3+5I if two moles of iodine are taken then the eatuo if iodate to iodide ion formed in the alkaline medium

Answer 1

Answer:

3 moles of $I_{2}$=1 mol of $IO_{3}$

1 Mole of $I_{2}$=1/3 mole $IO_{3}$

2 Moles of$I_{2}$=2/3 mole $IO_{3}$

Then the ratio is 1:5

Answer 2

Answer : The mole ratio of iodate $(IO_3^-)$ to iodide $(I^-)$ is, 1 : 5

Explanation :

The balanced chemical reaction in an alkaline medium will be,

$3I_2+6OH^-\rightarrow IO_3^-+5I^-+3H_2O$

First we have to calculate the moles of iodate $(IO_3^-)$ and iodide $(I^-)$.

From the balanced chemical reaction, we conclude that

As, 3 moles of $I_2$ react to give 1 mole of $(IO_3^-)$

So, 2 moles of $I_2$ react to give [tex[\frac{2}{3}=0.66mole[/tex] of $(IO_3^-)$

The moles of $(IO_3^-)$ = 0.66 mole

And,

As, 3 moles of $I_2$ react to give 5 moles of $(I^-)$

So, 2 moles of $I_2$ react to give [tex[\frac{2}{3}\times 5=3.33mole[/tex] of $(I^-)$

The moles of $(I^-)$ = 3.33 mole

Thus the mole ratio of $(IO_3^-):(I^-)$ = 0.66 : 3.33 = 1 : 5

Therefore, the mole ratio of iodate $(IO_3^-)$ to iodide $(I^-)$ is, 1 : 5