if in the right angled triangle ABC, <b=90° ,bc= 7cm , AC -AB =1cm ,then find the values of sin A and Cos A
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I assumed that AB and AC are the same and since AC-AB=1cm that AC is 8cm.
sin A=7cm÷8cm
sinA=0.875
A= sin^-1 0.875
A= 61°
cos A= 7cm÷8cm
cos A= 0.875
A= cos^-1 0.875
A= 29°
I hope this helped
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