Math, asked by vaishnavi9573, 4 months ago

if in the traingle PQR, angleQ=90°, PQ=4 cm and PR=9cm then find the value of..
1- sin P
2-cos A
3-tan D
4-sin R + cos R​

Answers

Answered by ayushbharti42
0

Step-by-step explanation:

Q=90

o

,

PQ=4cm

PR=9cm

By Pythagoras theorem

PR

2

=PQ

2

+QR

2

9

2

=4

2

+QR

2

36−16=QR

2

20=QR

2

QR=

20

=2

5

=4.47

sinP=

PR

QR

=

9

2

5

cosP=

PR

QP

=

9

4

tanR=sinR/cosR

=PQ/QR

=

2

5

4

=

5

2

sinR+cosR=

PR

PQ

+

PR

QR

=

9

4

+

9

2

5

=

9

4+2

5

.

Answered by shivajikaithi
2

Step-by-step explanation:

∠Q=90

o

,

PQ=4cm

PR=9cm

By Pythagoras theorem

PR

2

=PQ

2

+QR

2

9

2

=4

2

+QR

2

36−16=QR

2

20=QR

2

QR=

20

=2

5

=4.47

sinP=

PR

QR

=

9

2

5

cosP=

PR

QP

=

9

4

tanR=sinR/cosR

=PQ/QR

=

2

5

4

=

5

2

sinR+cosR=

PR

PQ

+

PR

QR

=

9

4

+

9

2

5

=

9

4+2

5

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.

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