if in the traingle PQR, angleQ=90°, PQ=4 cm and PR=9cm then find the value of..
1- sin P
2-cos A
3-tan D
4-sin R + cos R
Answers
Answered by
0
Step-by-step explanation:
Q=90
o
,
PQ=4cm
PR=9cm
By Pythagoras theorem
PR
2
=PQ
2
+QR
2
9
2
=4
2
+QR
2
36−16=QR
2
20=QR
2
QR=
20
=2
5
=4.47
sinP=
PR
QR
=
9
2
5
cosP=
PR
QP
=
9
4
tanR=sinR/cosR
=PQ/QR
=
2
5
4
=
5
2
sinR+cosR=
PR
PQ
+
PR
QR
=
9
4
+
9
2
5
=
9
4+2
5
.
Answered by
2
Step-by-step explanation:
∠Q=90
o
,
PQ=4cm
PR=9cm
By Pythagoras theorem
PR
2
=PQ
2
+QR
2
9
2
=4
2
+QR
2
36−16=QR
2
20=QR
2
QR=
20
=2
5
=4.47
sinP=
PR
QR
=
9
2
5
cosP=
PR
QP
=
9
4
tanR=sinR/cosR
=PQ/QR
=
2
5
4
=
5
2
sinR+cosR=
PR
PQ
+
PR
QR
=
9
4
+
9
2
5
=
9
4+2
5
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