Question

If in the word "AMPLENESSES" all the vowels at even places are replaced by 1, all consonants at even places are replaced by 2, vowels at odd places are replaced by 3, and all consonants at odd places are replaced by 4, then the sum of all digits of the number obtained by replacing the letters in given words

(1) 31
(2) 33
(3) 34
(4) 30

Answer 1

If we replace all the alphabets with numbers then we get 32423232414 as a result.So when we add them the result is 30.So your answer is also 20

Answer 2

Solution :-

AMPLENESSES

1) All the vowels at even places are replaced by 1

# There is only one vowel at 10th position, which is E.

⇒ E = 1

⇒ 1*1 = 1

2) All the consonants at even places are replaced by 2.

# There are 4 consonants in this word at even places, i.e. M at 2nd, L at 4th, N at 6th and S at 8th position respectively. 

⇒ M = 2, L = 2, N = 2 and S = 2

⇒ 2*4 = 8

3) All the vowels at odd places are replaced by 3.

# There are 3 vowels at odd places in this word, i.e. A at 1st, E at 5th and E at 7th position respectively.

⇒ A = 3, E = 3 and E = 3

⇒ 3*3 = 9

All the consonants at odd places are replaces by 4.

# There are 3 consonants at odd places, i.e. P at 3rd, S at 9th and S at 11th position respectively.

⇒ P = 4, S = 4 and S = 4

⇒ 4*3 = 12

Number obtained = 32423232414

Sum of all these digit = 

3 + 2 + 4 + 2 + 3 + 2 + 3 + 2 + 4 + 1 + 4 

= 30

So, sum of all these digits is 30.

Answer.