Math, asked by darkgalaxy5050, 5 months ago

if in tow triangle DEF and PQR , <D =<Q and <R=<E , then DE/PQ = FE/RP is true ? justify.

please give correct explanation .
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Answered by chintu098

Step-by-step explanation:

Step-by-step explanation:If in △DEF and △QRP

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠E

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRP

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQR

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE =

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE = RP

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE = RPEF

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE = RPEF =

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE = RPEF = PQ

Step-by-step explanation:If in △DEF and △QRP∠D=∠Q,∠R=∠EThen by AA similarity we have,△DEF∼△QRPQRDE = RPEF = PQDF

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