Question

if in trapezium AD||EF||BC if EB is 3AE and DF is 2.5 cm then length of FC

Answer 1

this is absolutely right answer.
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Answer 2

df=2.5
then AE=2.5 (since ADIIEF)
3AE=EB
3*2.5=EB
then EB=7.5
EB=FC as EFIIBC
therefore FC=7.5

hope it helps