If in triangle ABC, Ad is median AND AE perpendicular to BC then prove that
AB^2+AC^2=2AD^2+1/2BC^2
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in triangle ABC, AD is median
then , BD = BC
in triangles ABD and ADC
» AB² = AD² + BD²______( 1 )
» AC² = AD² + BC² _____(2)
› now add both the equations, ‹
» AB² + AC² = AD² + AD² + BD²+ BC²
» AB² + AC² = 2AD² + 2BD² [ since BD = BC]
» AB² + AC² = 2[AD² + BD²]
↪hence proved.↩
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