If in triangle abc, angle a + angle b= 120 deg and angle b + angle c = 100deg, then find angle b.
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A+B=120...................1
B+C=100........................2
ALSO, WE KNOW THAT A+B+C=180..............................3
I.E. A+B=180-C........................................4
FROM 1 & 4, WE GET 180-C=120
I.E. C=60
PUT C=60 IN 2, WE GET, B=40,
PUT B=40 IN 1, WE GET A=80
B+C=100........................2
ALSO, WE KNOW THAT A+B+C=180..............................3
I.E. A+B=180-C........................................4
FROM 1 & 4, WE GET 180-C=120
I.E. C=60
PUT C=60 IN 2, WE GET, B=40,
PUT B=40 IN 1, WE GET A=80
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