Math, asked by vdas422, 4 months ago

If in triangle ABC, b=90° and tan C=1/2 then find the value of sin A cos C-cos A sin C

Answers

Answered by devika862

0

Answer:

3/root5

Step-by-step explanation:

sinA=2/root5

CosC=2/root5

CosA=1/root5

sinC=1/root5

sinAcosC-CosAsinC=2/root5(2/root5)-1/root5(1/root5)

=4/root5-1/root5

=3/root5

Answered by aditya20203

0

Answer:

trigonometry was discovered by hipparchus

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