if in triangle ABC if median b and c perpendicular than cotb+cotc
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Given : in triangle ABC if median b and c perpendicular
To find : CotB + CotC
Solution:
if two medians are perpendicular
then it must be Equilateral Triangle
=> ∠A = ∠B = ∠C = 60°
CotB + CotC
= Cot60° + Cot60°
= 1/√3 + 1/√3
= 2/√3
cotb+cotc = 2/√3
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