If in triangle ABC, XY divides side AB and AC resp. And by B.P.T. AX/XB= AY/YC, then AB/ AC= AX/AY is true? If yes, then prove it.
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Yes it is true
here is the proof
AX/XB=AY/YC
XB/AX=YC/AY
(XB/AX)+1=(YC/AY)+1
(XB+AX)/AX=(YC+AY)/AY
AB/AX=AC/AY
by cross multiplication
AB/AC=AX/AY
hope it helps
good luck
here is the proof
AX/XB=AY/YC
XB/AX=YC/AY
(XB/AX)+1=(YC/AY)+1
(XB+AX)/AX=(YC+AY)/AY
AB/AX=AC/AY
by cross multiplication
AB/AC=AX/AY
hope it helps
good luck
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