If in triangle CAB and triangle FED , AB/EF =BC/FD, then (a) triangle ABC~triangle DEF (b) triangle CAB~ triangle DEF (c) triangle ABC~ triangle EFD
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Step-by-step explanation:
In △ABC and △DEF
⇒ The correspondence CAB↔EDF gives a congruence.
⇒ So, CA=ED,AB=DF,CB=EF
⇒ ∠CAB=∠EDF,∠ACB=∠DEF,∠ABC=∠DFE
∴ AB=EF is not true.
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