If in triangles ABC and EDF, FD BC DE AB = then they will be similar, when (A) ∠B = ∠E (B) ∠A = ∠D (C) ∠B = ∠D (D) ∠A = ∠F
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Angle formed by AB and BC is ∠B. Angle formed by DE and FD is ∠D. Therefore, the given triangles will be similar when ∠B = ∠D. Hence, (c) is the correct answer.
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