If in two triangles DEF and PQR, ∠D = ∠Q and ∠R = ∠E, then DE/PQ = FE/RP justify
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3
Answer:
If in △DEF and △QRP
∠D=∠Q,∠R=∠E
Then by AA similarity we have,
△DEF∼△QRP
QR
DE
=
RP
EF
=
PQ
DF
Thus, B is not correct.
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