Physics, asked by Programme, 9 months ago

If in vernier callipers 4 VSD coincides with 2 MSD, then least count of vernier calliper is [given 1 MSD = 1 mm]If , then will be equal to

Answers

Answered by renu51622
0

Answer:

Further, 4 main scale divisions coincide with 5 Vernier scale divisions (VSD) i.e., 4 MSD = 5 VSD. Thus, 1 VSD = 4/5 MSD = 0.1 cm. The least count of the Vernier calipers is given by LC = 1 MSD - 1 VSD = 0.125 - 0.1 = 0.025 cm.

Similar questions