if in ∆ Win and ∆ Fly
ar (Fly) = 98 sqcm and WN = 5/7 then ar (Win) = ? sqcm
options (9, 18, 42 , 49)
Answers
Answer:
Explanation:
Area of triangle =
2
1
[x
1
(y
2
−y
1
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
3
)]
=
2
1
[x(7−5)+5(5−y)−4(4−7)]
Given A,B and C are collinear, then area of triangle must be zero.
∴
2
1
[x(7−5)+5(5−y)−4(4−7)]=0
⇒
2
1
[2x−25+5y−4y+25]=0
⇒
2
1
(2x+y+3)=0
Then, relation between x and y is 2x+y+3=0
Given : ∆WIN~∆FLY, ar (FLY) = 98 cm² and WN/FY = 3/7,
To find : ar (WIN)
Solution:
Ratio of Area of similar triangle = ( ratio of corresponding sides )²
∆WIN~∆FLY
=> WN and FY are corresponding sides
ar (WIN) / ar (FLY) = (WN/ FY ) ²
=> ar (WIN) / 98 = (3/ 7 ) ²
=> ar (WIN) / 98 = 9/49
=> ar (WIN) = 9 * 2
=> ar (WIN) = 18
ar (WIN) = 18 cm²
Learn More:
Ratio of area of 2 similar triangles are 2:3. Area of the larger triangle is
brainly.in/question/7877543
if triangle abc- triangle def area of triangle abc is 64 square ...
brainly.in/question/14594418
Three triangles are marked out of a bigger triangle at the three ...
brainly.in/question/8018381