If inclination of the line (2-k)r-(1-k)y+(5-26)=0 is then the value of Ais 4. O 2 O 3/2 0 2/13 4/5
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0
Answer:
Answer
Correct option is
D
2
3
(2−k)x−(1−k)y+(5−2k)=0
m=tan
4
3π
=−1
∴slope=m=−1=
k−1
k−2
k−1=2−k
k=
2
3
Answered by
0
Answer:
ans=
2
3
Step-by-step explanation:
(2−k)r−(1−k)y+(5−2k)=0
m=tan
4
3π
=−1
∴slope=m=−1=
k−1
k−2
k−1=2−k
k=
2
3
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