Math, asked by bidiyasarmanish4628, 1 year ago

If income of a, b, c are in the ratio of 2 : 9 : 11 and income of b is rs.280 more than that of a, what is the income of c?

Answers

Answered by praneethks
11
let the incomes of a,b,c be 2k,9k,11k. Difference between incomes of b and a is ₹280=> 9k-2k=7k=
₹280=> k=₹ 280/7=₹40. So income of c is 11(40)=₹440.
Answered by amitnrw
6

income of c =  440 Rs If income of a, b, c are in the ratio of 2 : 9 : 11 and income of b is rs.280 more than that of a

Step-by-step explanation:

income of a, b, c are in the ratio of 2 : 9 : 11

Let say income of a  = 2K  Rs

then income of b = 9K  Rs

& income of c = 11K  Rs

income of b is rs.280 more than that of a

=> 9K = 2K + 280

=> 7K = 280

=> K = 40

income of c = 11K = 11 * 40  = 440 Rs

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