If income of a, b, c are in the ratio of 2 : 9 : 11 and income of b is rs.280 more than that of a, what is the income of c?
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let the incomes of a,b,c be 2k,9k,11k. Difference between incomes of b and a is ₹280=> 9k-2k=7k=
₹280=> k=₹ 280/7=₹40. So income of c is 11(40)=₹440.
₹280=> k=₹ 280/7=₹40. So income of c is 11(40)=₹440.
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income of c = 440 Rs If income of a, b, c are in the ratio of 2 : 9 : 11 and income of b is rs.280 more than that of a
Step-by-step explanation:
income of a, b, c are in the ratio of 2 : 9 : 11
Let say income of a = 2K Rs
then income of b = 9K Rs
& income of c = 11K Rs
income of b is rs.280 more than that of a
=> 9K = 2K + 280
=> 7K = 280
=> K = 40
income of c = 11K = 11 * 40 = 440 Rs
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