if increase in linear momentum of a body is 50%, Then charge in its kinetic energy is?
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125% charge in its kinetic energy
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p= MV
If P increases by 50% , the new Momentum will be:-
p'= p+p/2=3p/2
Initial kinetic energy,
k=1/2 MV^2
The new kinetic energy,
K'= 1/2 MV^2 ×M/M
k'= p'^2/2M
k'/k= p'^2/2M/ p^2/2M
k'/k= p'^2/p^2 (p'=3p/2)
k'/k = (3p/2)^2/ p^2
k'/k = 9/4
% change = {(k'-k)×100%}/k= {5×100%}/4
% change = 125%
"MARK AS BRAINLEAST."
If P increases by 50% , the new Momentum will be:-
p'= p+p/2=3p/2
Initial kinetic energy,
k=1/2 MV^2
The new kinetic energy,
K'= 1/2 MV^2 ×M/M
k'= p'^2/2M
k'/k= p'^2/2M/ p^2/2M
k'/k= p'^2/p^2 (p'=3p/2)
k'/k = (3p/2)^2/ p^2
k'/k = 9/4
% change = {(k'-k)×100%}/k= {5×100%}/4
% change = 125%
"MARK AS BRAINLEAST."
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